Let S = 2x+5x2+9x3+14x4+20x5+… infinity. The coefficient of nth
term is n(n+3)/2. The sum S is:
Solution:
(1)x(2-x)/(1-x)3 (2) (2-x)/(1-x)3 (3) x(2-x)/(1-x)2 (4)None of these
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It is a standard model which deals
with manipulation and simplification of equations.
S = 2x+5x2+9x3+14x4+20x5+….
-----(1)
Multiplying on both sides with 'x':
Multiplying on both sides with 'x':
xS = 2x2+5x3+9x4+14x5+20x6+…. -----(2)
(1)-(2) gives
(1-x)S = 2x+3x2+4x3+5x4+… ------(3)
Multiplying on both sides with 'x':
x(1-x)S = 2x2+3x3+4x4+5x5+… ------(4)
x(1-x)S = 2x2+3x3+4x4+5x5+… ------(4)
(3)-(4) gives
(1-x)(1-x)S = 2x+x2+x3+x4+…
(1-x)2S = x+(x+x2+x3+x4+…... infinite terms)
(1-x)2S
= x + (sum of G.P with initial term ‘x’ and common ratio ‘x’)
“Formula:
sum of infinite G.P = a/(1-r), where a is initial term and r is common ratio”
(1-x)2S
= x + x/(1-x) = (x-x2+x)/(1-x) = (2x-x2)/(1-x) = x(2-x)/(1-x)
=> S
= x(2-x)/(1-x)3
Answer (1)
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