## Sunday, 6 November 2011

### Puzzle-9 (XAT-2009)

A company BELIANCE hosted a party for 8 members of company AXIAL. In the party no member of AXIAL had interacted with more than three members of BELIANCE. Out of all the members of BELIANCE, three members- each interacted with four members of AXIAL and the remaining members – each interacted with two members of AXIAL. The greatest possible number of members of company BELIANCE in the party is:
A.9      B. 10               C. 11               D. 12               E. None of these
Solution follows here:

Solution:
Given number of members in AXIAL = 8
In the party no member of AXIAL had interacted with more than three members of BELIANCE => Maximum number of interactions would be = 8*3 = 24.
Out of all the members of BELIANCE, three members- each interacted with four members of AXIAL” =>number of interactions of these 3 members of BELIANCE= 3*4 = 12 => remaining number of interactions for BELIANCE = 24-12 = 12
“and the remaining members – each interacted with two members of AXIAL => remaining number of members in BELIANCE = 12/2 = 6
Maximum number of members in BELIANCE = 6+3 = 9