In a class, 30 students pass in English, and 20 students in Math, while
some students among these pass in both. How many more students do only English,
as compared to those doing only Math?

It’s a simple set theory problem.

(1)10
(2)15 (3)20 (4) Indeterminate

Solution
follows here:

__Solution:__It’s a simple set theory problem.

Number of
students passed in English = n(E) = 30

Number of
students passed in Math = n(M) = 20

Let number
of students passed in both = n(E∩M) = x;

Number of
students passed in only English = n(E)- n(E∩M) = 30-x ------(1)

Number of
students passed in only Math = n(M)- n(E∩M) = 20-x ------(2)

Difference
between (1) and (2) gives then number of students do only English, as compared
to those doing only Math.

(30-x)-(20-x)
=

**10****Answer (1)**
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