A
contract on construction job specifies a penalty for delay in completion of
work beyond a certain date is as follows:

Solution follows here:

Rs
200 for the first day, Rs 250 for the second day, Rs 300 for the third day
etc..,. The penalty for each succeeding day is Rs 50 more than the preceding
day. How much penalty should the contractor pay if he delays the work by 10
days?

(A)
Rs 4950

(B)
Rs 4250

(C)
Rs 3600

(D) Rs 650Solution follows here:

__Solution:__
Penalty is ----- Rs 200 for the
first day, Rs 250 for the second day, Rs 300 for the third day...

Penalty per day follows an
arithmetic progression: 200,250,300,....

With initial term = a = 200 and
common difference = d = 50.

Here we have two formulae, one is
for n

^{th}term in A.P,**t**_{n}= a+(n-1)d
and the second one is Sum of n-terms
in A.P,

**S**_{n}= n/2 * {2a+(n-1)d}
The only chance of mistake in this
problem is here: whether to find penalty on 10

^{th}day or penalty for 10 days. It is asked that “How much penalty should the contractor pay if he delays the work by 10 days”
=> it is asked -penalty for 10
days

=> Sum to n-terms formula
should be used

=> S

_{n}= 10/2 * (2*200 + 9*50) = 5*850 =**4250**
If we go on the wrong way and
find out t

_{n, }we get 650, which is also available in the answer options. So, here we should be careful.**Answer(2)**
option d

ReplyDeleteNo, it is not asked for the penalty on 10th day but penalty for 10 days

ReplyDelete