Wednesday, 14 December 2011

Numbers - 20

Using only 2,5,10,25 and 50 paise coins, What will be the minimum number of coins required to pay exactly 78 paise,69 paise and Rs 1.01 to three different persons?
(1)19               (2)20               (3)17               (4)18
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2 comments:

  1. TSK15 December 2011 at 10:13

    Answer (1)19

    78paise=50paise+2*(10paise)+4*(2paise) = 7coins

    69paise=50paise+10paise+5paise+2*(2paise)=5coins

    Rs.1.01=50paise+25paise+2*(10paise)+3*(2paise)=7coins

    So, totally 19 coins (7 + 5 + 7)

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  2. MathByVemuri15 December 2011 at 21:55

    TSK, your answer is correct.

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