In a triangle ABC, the lengths of the sides AB and AC
equal 17.5cm and 9cm respectively. Let D be a point on the line segment BC such
that AD is perpendicular to BC. If AD=3cm, then what is the radius (in cm) of
the circle circumscribing the triangle ABC?

(1)17.05 (2) 27.85
(3) 22.45 (4) 32.25 (5) 26.25

Solution follows here:

__Solution:__
It is a simple
formula based trigonometric one.

**AB = c = 17.5;AC = b = 9; Let base = BC = a; height = AD = 3;**

__Given:__**circum radius = R**

__To find:__
Area of
the triangle ABC =

**Δ****=****½ (BC)(AD)**= ½ (a)(3) = 3a/2
The
formula here is :

**R = abc/4Δ**= abc / 4(3a/2) = bc/6 = (17.5)(9)/6 = 26.25**Answer (5)**
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