Tuesday 11 October 2011

Puzzle-3 (CSAT-2011)

Study the following figure:

A person goes from A to B always moving to the right or down along the lines.
How many different routes can he adopt?
(a)8        (b) 7           (c) 6            (d) 5
Solution follows here:

Solution:
The possible routes are A123B, A143B, A147B, A543B, A547B, A567B. Total 6 routes. 
Answer (c)


Note:
Best solution for similar type of problems can be found at the below link:



3 comments:

  1. The best mathematical solution I read for this sort of problems is like this:
    The number of horizontal lines required to go from A to B= 2
    The number of horizontal lines required to go from A to B = 2
    Total number of ways = (2+2)C2 = 4C2 = 6
    But, I could not figure out how he arrived at this formula? Which logic/concept used here?
    One thing for sure is this logic works out for similar types with more horizontal and vertical lines.
    Any Idea??

    ReplyDelete
  2. check out for best solution for these type of problems in the Puzzle-28 on this blog.

    ReplyDelete
  3. thanks! much appreciated!

    ReplyDelete