__Related Concepts:-__
Length of arc = (angle made by the arc at the centre) * (2πr) / 360

^{0}
Area of circular region covered under arc

= (angle made by the arc at the centre) * (πr

= (angle made by the arc at the centre) * (πr

^{2}) / 360^{0}
Circumference of the circle = 2πr

(This is the arc length for complete 360

^{0}angle made at the centre)
ÐAOB = ÐCOD ÐAOC = ÐBOD

Length of arc AB = length of arc CD

Length of arc AC = length of arc BD

__The possible quant-comparison Q’s in GRE:__
Each question from Q1 to Q5 consists of two quantities, one in column A and one in column B. You are to compare the two quantities and choose

A if the quantity in column A is greater;

B if the quantity in column B is greater;

C if the quantities are equal;

B if the relationship cannot be determined from the information given;

**Q1**)

__Column A__

__Column B__

Length of arc AB Length of arc CD

**Q2**)

__Column A__

__Column B__

Length of arc AC Length of arc BD

**Q3**) Given that ÐAOB is acute angle

__Column A__

__Column B__

Length of arc AB Length of arc BD

**Q4**)

__Column A__

__Column B__

Area of shaded region AOB Area of shaded region COD

**Q5**)

__Column A__

__Column B__

Area of un-shaded region AOC Area of un-shaded region BOD

__The possible problem-solving Q’s in GRE/GMAT:__**Q6**) If the ÐAOB = 60

^{0 }and radius of the circle is 4 units

_{, }find the length of arc AB

_{}

**Q7**) If the ÐAOB = 60

^{0}and the radius of the circle is 3 units

_{, }find the total area of shaded region

**Q8**) If a straight-line is drawn joining A and B and given that the ÐAOB = 60

^{0 }and

radius measures 3 units

_{, }find the length of the straight-line AB**Q9)**If length of arc ACDB is double that of arc AB, then find ÐAOB**Please find the solutions to these problems in the next post on this blog.**

**Note:-**

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