Consider obtuse angled triangles with sides 8 cm, 15
cm and x cm. If x is an integer, then how many such triangles exist?
(1)5 (2)21 (3)10 (4) 15 (5) 14
Solution follows here:
Solution:
(1)5 (2)21 (3)10 (4) 15 (5) 14
Solution follows here:
Solution:
Here two theorems come into picture.
One is Pythagoras for obtuse triangle: c2>a2+b2,
where c is the biggest side of the three
Second one is Triangle inequality theorem: Sum of two
sides of a triangle must be greater than the measure of the third side. c < a+b, where c is the biggest side of
the three.
Case-I: x is the
biggest side:
All possibilities of x according to triangle
inequality theorem, are 22,21,20,19,18,17,16,15.
But 82+152 = 64+225 = 289 = 172,
hence as per Pythagoras, we can consider values above 17 only. x=22,21,20,19,18
Case-II: 15 is the biggest side:
All possibilities of x according to triangle
inequality theorem, are 8,9,10,11,12,13,14.
But 152 - 82 = 225-64 = 161 <
132, hence as per Pythagoras, we can consider values less than 13
only. x=8,9,10,11,12
All possible values of x = 8,9,10,11,12,18,19,20,21,22
Total 10 values
Answer(3)
good one
ReplyDeleteIs 15 given ist step possible as x must be greater than 15
ReplyDeleteCan x take as given in 1st step. as x must be greater than 15
ReplyDelete