If
the sum of first n terms of A.P is cn2, then the sum of squares of
these n terms is:
(a)n(4n2-1)c2/6
(b) n(4n2+1)c2/3
(c) n(4n2-1)c2/3 (d) n(4n2+1)c2/6
Solution
follows here:
H
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G
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A
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B
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O
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C
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D
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E
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F
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